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Replace characters in string in 4GL
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Replace characters in string in 4GL
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Lorena
Advanced Member
Posts: 37
3/26/2013 11:32 AM
Hi,
I need to replace spaces by _ in a string in 4GL.
Does anyone know if Lawson provides any routine for this?
Example:
Input: Boca Raton
Output: Boca_Raton
Thanks,
Lorena
Woozy
Veteran Member
Posts: 709
3/26/2013 12:58 PM
The cobol "INSPECT" should do this for you:
INSPECT {VARIABLE} REPLACING ALL " " BY "_".
Lorena
Advanced Member
Posts: 37
3/26/2013 3:41 PM
Thank you.
maalimsimo
Veteran Member
Posts: 49
7/18/2013 1:18 PM
In trying to replace Carriage Return and Line Feed characters from a string (CMTAPI), I have tried to use INSPECT CMTAPI-EXT-TEXT REPLACING ALL x"0D" BY SPACES (for CR) and x"0A" (for LF). None seems to achieve my desired end as my output file still breaks up into two lines at the point where the user has put a hard return.
Any idea what else I need to try? A lot of Lawson pgms have x"A" replaced - what character is this?
Woozy
Veteran Member
Posts: 709
7/18/2013 1:48 PM
Hi maalimsimo,
I haven't tried this, but I have a couple of suggestions for you to try.
First, use a capital "X" rather than "x", so INSPECT CMTAPI-EXT-TEXT REPLACING ALL X"0D" BY SPACES
Second, if it is a CRLF then try INSPECT CMTAPI-EXT-TEXT REPLACING ALL X"0D0A" BY SPACES
Good Luck.
Woozy
Veteran Member
Posts: 709
7/18/2013 1:52 PM
Actually, LineFeed may be "25" instead of "0A", so if the other doesn't work, try INSPECT CMTAPI-EXT-TEXT REPLACING ALL X"0D25" BY SPACES
maalimsimo
Veteran Member
Posts: 49
7/18/2013 1:53 PM
Never mind, it was a error in placement of the INSPECT statement in my code. It works just fine now
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