Replace characters in string in 4GL

The cobol "INSPECT" should do this for you:

INSPECT {VARIABLE} REPLACING ALL " " BY "_".

Thank you.

In trying to replace Carriage Return and Line Feed characters from a string (CMTAPI), I have tried to use INSPECT CMTAPI-EXT-TEXT REPLACING ALL x"0D" BY SPACES (for CR) and x"0A" (for LF). None seems to achieve my desired end as my output file still breaks up into two lines at the point where the user has put a hard return.
Any idea what else I need to try? A lot of Lawson pgms have x"A" replaced - what character is this?

Hi maalimsimo,

I haven't tried this, but I have a couple of suggestions for you to try. 

First, use a capital "X" rather than "x", so INSPECT CMTAPI-EXT-TEXT REPLACING ALL X"0D" BY SPACES
Second, if it is a CRLF then try INSPECT CMTAPI-EXT-TEXT REPLACING ALL X"0D0A" BY SPACES

Good Luck.

Actually, LineFeed may be "25" instead of "0A", so if the other doesn't work, try  INSPECT CMTAPI-EXT-TEXT REPLACING ALL X"0D25" BY SPACES 

Never mind, it was a error in placement of the INSPECT statement in my code. It works just fine now